The +Plus PerfectBlack Jack Strategy   Information and fun things about BLACK JACK ~ 21 ~  
On the net Since 1994
How will I know which Answer Table to use?

aj_imag2.gif (1013 bytes)  "You use the Answer table that has the answer", is the simple answer! Check the tables in this order:   Doubling table --> Splitting table --> Standing table.


Hit or double down?

Let’s say you want to know if you should hit or double down.

Here’s a rather obvious scenario: Suppose I’m dealt a 7 and a 5 for a total of 12. The Dealer has a 6. Should I hit or double down? Here’s what to do: First look in the Hard Doubling table to find the row labeled 12. But there is no row "12", so I deduce this table does not apply. I don’t have a pair, so the Pair Splitting

table doesn’t apply. Therefore the Hard Standing Number table remains to be interrogated. It will tell me the answer, because it has the square which I am "on" -- at the intersection of row 12 and column 6. The value shown there is [0]. More about how to use this answer later.

Split or hit?

Imagine you have a pair of 9’s and the dealer shows a 10.

You want to know if you should hit or split the pair you hold, or if you should double down. Follow the rule: Doubling --> Splitting --> Standing (DSS).

Hard Doubling table doesn’t apply, because there is no row labeled 18 (9+9).

The Pair Splitting table advises to do nothing in regard to splitting—there is nothing at the square at the intersection of the 9,9 row and the 10 column.

A hand total of 18 tells us we must stand because it is above the shaded STAND demarcation of row seventeen in the Hard Standing table.


Let’s say you have a pair of 4’s and the dealer shows a 9.

You want to know if you should hit, split, or double down. Follow the same DSS rule.

The Hard Doubling table has no answer in the square at row 8 and column 9. So we go to the next table, the Splitting table.

The Pair Splitting table does not advise us the square at row 4,4 and the 10 column is blank, so we must continue.

Again, a hand total of 8 is below the beginning of the Hard Standing table and we should HIT.

Once more

Let’s say you have a pair of 8’s and the dealer shows almost anything except an ace. The Hard Doubling table tells us to SPLIT.

Last Example

Finally, say you have a soft A,6 and the dealer shows a 3. The Soft Doubling table has a [-1] at that intersection. This [-1] is the answer that we compare against our count, and we will show later how to do that. Suppose this comparison tells us to NOT DOUBLE. We continue to the Soft Standing table to see what to do. It tells us to HIT for 17,3. Suppose we now get a 10, giving us a hard hand of 17. We must now ask the Hard Standing Number table what to do. In that table, at 17, 3 the advice is to STAND.


When you question what to do, just ask the Answer Table

We have purposely and laboriously stepped through the procedure of asking the Answer Tables. In Most cases the order in which you interrogate the tables is intuitively obvious. But we see that the DSS sequence always is the correct choice. The underlying principle is easy. Next we will learn how to ‘count’ and how to combine the count with our square in the answer table.

The COUNT demystified

aj_imag2.gif (1013 bytes)  It’s called ‘card counting’ because you are counting how many of each kind of card you see during play. Many people believe that card counters remember or count every card played. Not so! Most Black Jack Strategies only keep track of certain kinds of cards—categories. The categories of cards with which the +Plus Perfect Black Jack Strategy concerns itself are few: TENs, Non-TENs and EIGHTs. Aces are not Tens -— they count as non-Tens!

That’s it!

The single-deck game

This strategy was designed for multiple deck games as well as for single deck games. For now, assume that we are playing against one deck. Very little changes when you play against a shoe  of more than one deck, and we’ll see that later.

How it works.

The strategy works by letting you know the relative abundance of 10s in the deck.
Let’s consider just one deck of 52 cards. It contains

16 Tens
32 Non-Tens
  4 Eights

Let’s assign count-values to the Tens and non-Tens so that a full deck, [omitted here ...].

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